8x+10=x^2-38

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Solution for 8x+10=x^2-38 equation:


Simplifying
8x + 10 = x2 + -38

Reorder the terms:
10 + 8x = x2 + -38

Reorder the terms:
10 + 8x = -38 + x2

Solving
10 + 8x = -38 + x2

Solving for variable 'x'.

Reorder the terms:
10 + 38 + 8x + -1x2 = -38 + x2 + 38 + -1x2

Combine like terms: 10 + 38 = 48
48 + 8x + -1x2 = -38 + x2 + 38 + -1x2

Reorder the terms:
48 + 8x + -1x2 = -38 + 38 + x2 + -1x2

Combine like terms: -38 + 38 = 0
48 + 8x + -1x2 = 0 + x2 + -1x2
48 + 8x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
48 + 8x + -1x2 = 0

Factor a trinomial.
(12 + -1x)(4 + x) = 0

Subproblem 1

Set the factor '(12 + -1x)' equal to zero and attempt to solve: Simplifying 12 + -1x = 0 Solving 12 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1x = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1x = 0 + -12 -1x = 0 + -12 Combine like terms: 0 + -12 = -12 -1x = -12 Divide each side by '-1'. x = 12 Simplifying x = 12

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {12, -4}

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